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Andhra Pradesh DSC 2024: Normalization Formula
Normalization mark of jth candidate in ith shift ij is given by: M-M Ma-Mu-Mi (Mu-Miq)+M
M normalized marks of jth candidate in the ith shift
M = is the average marks of the top 0.1% of the candidates considering allshifts (number of candidates will be rounded-up)
M is the sum of mean and standard deviation marks of the candidates in the examination considering all shifts
My is the average marks of the top 0.1% of the candidates in the ith shift (number of candidates will be rounded up)
Ma is the sum of mean marks and standard deviation of the ith shift
My is the actual marks obtained by the jth candidate in the ith shift
Mom is the sum of mean marks of candidates in the shift having maximum mean and standard deviation of marks of candidates in the examination considering all
NOTE: Calculation of marks will be up to 5 decimal places.
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